What is the perpendicular y= 8/3 x-2,(-8,-6) ?

The perpendicular y= 8/3 x-2,(-8,-6) is y=-3/8 x-9

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perpendicular y= 8/3 x-2,(-8,-6)

perpendicular

y = \frac{8}{3} x - 2, (- 8, - 6)

y = - \frac{3}{8} x - 9

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{8}{3} x - 2

that passes through

(- 8, - 6)

Find the slope of

y = \frac{8}{3} x - 2 : m = \frac{8}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{8}

Find the line with slope m=

- \frac{3}{8}

and passing through

(- 8, - 6) : y = - \frac{3}{8} x - 9

y = - \frac{3}{8} x - 9

f (x) = (\frac{8}{3})^{x}

f (x) = \frac{7 - 2 x}{5}

\frac{17}{3} (- 2 - 6)

f (x) = 2 sin^{2} (x)

sin (7 x)

What is the perpendicular y= 8/3 x-2,(-8,-6) ?
The perpendicular y= 8/3 x-2,(-8,-6) is y=-3/8 x-9