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Popular >

range of f(x)=-x^2+6x-9

Solution

range

f (x) = - x^{2} + 6 x - 9

Solution

f (x) \leq 0

+1

Interval Notation

(- \infty, 0]

Solution steps

Vertex of

- x^{2} + 6 x - 9 :

Maximum

(3, 0)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (3, 0)

f (x) \leq 0

Popular Examples

inverse of f(x)=-1/3 x-7 inverse

f (x) = - \frac{1}{3} x - 7

inverse of tan(3x-5)inverse

tan (3 x - 5)

domain of sqrt(y-5)domain

y - 5

asymptotes of f(x)=(3x^2+3x)/(x^2-x)asymptotes

f (x) = \frac{3 x ^{2} + 3 x}{x ^{2} - x}

inverse of f(x)=3(x+2)^2-6 inverse

f (x) = 3 (x + 2)^{2} - 6

Frequently Asked Questions (FAQ)

What is the range of f(x)=-x^2+6x-9 ?
The range of f(x)=-x^2+6x-9 is f(x)<= 0