What is the extreme f(x)=x^3-3x-2 ?

The extreme f(x)=x^3-3x-2 is Maximum(-1,0),Minimum(1,-4)

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extreme f(x)=x^3-3x-2

extreme points

f (x) = x^{3} - 3 x - 2

Maximum (- 1, 0), Minimum (1, - 4)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x - 2 : 0

Maximum (- 1, 0)

Plug

x = 1

into

x^{3} - 3 x - 2 : - 4

Minimum (1, - 4)

Maximum (- 1, 0), Minimum (1, - 4)

3 x + 6 y = 6

f (x) = 2 x^{2} + 2 x - 3

f (x) = - x^{2} - 1

\frac{x ^{2} - x - 2}{x - 1}

1 - 2 x - 3

What is the extreme f(x)=x^3-3x-2 ?
The extreme f(x)=x^3-3x-2 is Maximum(-1,0),Minimum(1,-4)