What is the inverse of f(x)=sqrt(x^2-9x) ?

The inverse of f(x)=sqrt(x^2-9x) is (9+sqrt(81+4x^2))/2 ,(9-sqrt(81+4x^2))/2

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inverse of f(x)=sqrt(x^2-9x)

inverse

f (x) = x^{2} - 9 x

\frac{9 + 81 + 4 x ^{2}}{2}, \frac{9 - 81 + 4 x ^{2}}{2}

Solution steps

y = x^{2} - 9 x

Replace

x

with

y

x = y^{2} - 9 y

Solve for

y, x = y^{2} - 9 y

\frac{9 + 81 + 4 x ^{2}}{2}, \frac{9 - 81 + 4 x ^{2}}{2}

f (x) = \frac{x - 3}{x + 3}

f (x) = \frac{5 e ^{x}}{e ^{x} - 8}

\frac{- 3 x - 2}{x + 3}

f (x) = 2 cos (\frac{x}{4})

5

What is the inverse of f(x)=sqrt(x^2-9x) ?
The inverse of f(x)=sqrt(x^2-9x) is (9+sqrt(81+4x^2))/2 ,(9-sqrt(81+4x^2))/2