What is the critical (x^3)/(x^2+3) ?

The critical (x^3)/(x^2+3) is x=0

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critical (x^3)/(x^2+3)

critical points

\frac{x ^{3}}{x ^{2} + 3}

x = 0

Solution steps

\frac{x ^{3}}{x ^{2} + 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{x ^{2} + 3} : - \infty < x < \infty

All critical points are in domain

x = 0

f (x) = 3 x^{2}

f (x) = \frac{x}{x ^{2} - 1}

x

2 x^{2} + 4 x - 10

cos (2 x + 5)