What is the domain of f(x)= 1/(2x-1) ?

The domain of f(x)= 1/(2x-1) is x 1/2

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domain of f(x)= 1/(2x-1)

domain

f (x) = \frac{1}{2 x - 1}

x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}

The function domain

x < \frac{1}{2} or x > \frac{1}{2}

f (x) = 4 x - 16

- x^{2} + 6 x - 2

- 2^{- x + 3} - 2

f (x) = 2 (x + 1)

1 + 2 + 3 x

What is the domain of f(x)= 1/(2x-1) ?
The domain of f(x)= 1/(2x-1) is x< 1/2 \lor x> 1/2