What is the inverse of f(x)=(7x+8)/(8x-3) ?

The inverse of f(x)=(7x+8)/(8x-3) is (8+3x)/(8x-7)

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inverse of f(x)=(7x+8)/(8x-3)

inverse

f (x) = \frac{7 x + 8}{8 x - 3}

\frac{8 + 3 x}{8 x - 7}

Solution steps

y = \frac{7 x + 8}{8 x - 3}

Replace

x

with

y

x = \frac{7 y + 8}{8 y - 3}

Solve for

y, x = \frac{7 y + 8}{8 y - 3}

\frac{8 + 3 x}{8 x - 7}

f (x) = (x - 4)^{2} - 9

y = arcsin (- 2)

8 x + 9

(x - 2)^{2} - 4

f (x) = sin (- x)

What is the inverse of f(x)=(7x+8)/(8x-3) ?
The inverse of f(x)=(7x+8)/(8x-3) is (8+3x)/(8x-7)