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Popular >

midpoint (4,2),(4,1)

Solution

midpoint

(4, 2), (4, 1)

Solution

(4, \frac{3}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (4, 2), (x_{2}, y_{2}) = (4, 1)

= (\frac{4 + 4}{2}, \frac{1 + 2}{2})

Refine

= (4, \frac{3}{2})

Popular Examples

domain of f(x)= 1/(arccos(x-2))domain

f (x) = \frac{1}{arccos ( x - 2 )}

inverse of f(x)=(x+5)inverse

f (x) = (x + 5)

domain of (x^2-x-2)/(x^2-6x+9)domain

\frac{x ^{2} - x - 2}{x ^{2} - 6 x + 9}

critical f(x)=2x^3-21x^2+60x+3 critical points

f (x) = 2 x^{3} - 21 x^{2} + 60 x + 3

domain of sqrt(x+4)+6 domain

x + 4 + 6

Frequently Asked Questions (FAQ)

What is the midpoint (4,2),(4,1) ?
The midpoint (4,2),(4,1) is (4, 3/2)