What is the inverse of f(x)=(x+4)^{1/5}+3 ?

The inverse of f(x)=(x+4)^{1/5}+3 is x^5-15x^4+90x^3-270x^2+405x-247

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inverse of f(x)=(x+4)^{1/5}+3

inverse

f (x) = (x + 4)^{\frac{1}{5}} + 3

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 247

Solution steps

y = (x + 4)^{\frac{1}{5}} + 3

Replace

x

with

y

x = (y + 4)^{\frac{1}{5}} + 3

Solve for

y, x = (y + 4)^{\frac{1}{5}} + 3

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 247

F (X) = X^{5}

f (x) = \frac{7 + 2 x}{x}

f (x) = \frac{5}{( \frac{11}{x} ) + 2}

tan (x)

\frac{1 - 2 x}{6 + x}

What is the inverse of f(x)=(x+4)^{1/5}+3 ?
The inverse of f(x)=(x+4)^{1/5}+3 is x^5-15x^4+90x^3-270x^2+405x-247