What is the domain of sqrt(x^2+x-2) ?

The domain of sqrt(x^2+x-2) is x = 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(x^2+x-2)

domain

x^{2} + x - 2

x \leq - 2 or x \geq 1

Interval Notation

(- \infty, - 2] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 1

The function domain

x \leq - 2 or x \geq 1

f (x) = - 4 x - 39

f (x) = 5^{x}

f (x) = (x + 3) e^{- x}

f (x) = \frac{( x ^{2} )}{x - 5}

f (x) = - 2 x^{2} + 6 x + 10

What is the domain of sqrt(x^2+x-2) ?
The domain of sqrt(x^2+x-2) is x<=-2\lor x>= 1