What is the domain of y=-sqrt(x^2-1) ?

The domain of y=-sqrt(x^2-1) is x = 1

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domain of y=-sqrt(x^2-1)

domain

y = - x^{2} - 1

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

f (x) = \frac{x ^{2} - 1}{x + 6}

f (x) = 2^{x} + 2

f (x) = x + 1 - x

y = - 6 x + 4

f (x) = \frac{3}{( x ^{2} - 2 x )}

What is the domain of y=-sqrt(x^2-1) ?
The domain of y=-sqrt(x^2-1) is x<=-1\lor x>= 1