What is the range of f(x)=(1-x)/(x+2) ?

The range of f(x)=(1-x)/(x+2) is f(x) -1

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range of f(x)=(1-x)/(x+2)

range

f (x) = \frac{1 - x}{x + 2}

f (x) < - 1 or f (x) > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1 - x}{x + 2}

Inverse of

\frac{1 - x}{x + 2} : \frac{1 - 2 x}{x + 1}

\frac{1 - 2 x}{x + 1}

Find the domain of each inverse function

Domain of

\frac{1 - 2 x}{x + 1} : x < - 1 or x > - 1

Combine the intervals

f (x) < - 1 or f (x) > - 1

f (x) = 1 - ln (x)

f (x) = \frac{x ^{2}}{2 ^{x}}

f (x, y) = \frac{5 x}{ln ( x ^{2} - 4 )}

4 x - 5

y = 4 x + 3

What is the range of f(x)=(1-x)/(x+2) ?
The range of f(x)=(1-x)/(x+2) is f(x)<-1\lor f(x)>-1