What is the inverse of f(x)=((x^{-0.03}-1))/(-0.03) ?

The inverse of f(x)=((x^{-0.03}-1))/(-0.03) is cube root of 1/((x*0.03-1)^{100)}

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inverse of f(x)=((x^{-0.03}-1))/(-0.03)

inverse

f (x) = \frac{( x ^{- 0.03} - 1 )}{- 0.03}

Solution steps

y = \frac{x ^{- 0.03} - 1}{- 0.03}

Replace

x

with

y

x = \frac{y ^{- 0.03} - 1}{- 0.03}

Solve for

y, x = \frac{y ^{- 0.03} - 1}{- 0.03}

y - 3 = 3 (x - 6)

f (x) = \frac{- 4 x - 12}{x ^{2} - 9}

x + 33

y = lo g_{10} (x)

f (x) = x^{4} (x - 2) (x + 3)

What is the inverse of f(x)=((x^{-0.03}-1))/(-0.03) ?
The inverse of f(x)=((x^{-0.03}-1))/(-0.03) is cube root of 1/((x*0.03-1)^{100)}