What is the domain of (x+1)/(x^2-x-6) ?

The domain of (x+1)/(x^2-x-6) is x 3

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domain of (x+1)/(x^2-x-6)

domain

\frac{x + 1}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

\frac{( 3 x ^{3} - x ^{2} - 27 x + 9 )}{x ^{2} + 4 x + 3}

f (x) = 16 - x^{2}

x - y = - 1

f (x) = 1 0^{\frac{x}{2}}

f (x) = lo g_{7} (x)

What is the domain of (x+1)/(x^2-x-6) ?
The domain of (x+1)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3