What is the parallel y= 3/2 x+3,(1,-2) ?

The parallel y= 3/2 x+3,(1,-2) is y= 3/2 x-7/2

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parallel y= 3/2 x+3,(1,-2)

parallel

y = \frac{3}{2} x + 3, (1, - 2)

y = \frac{3}{2} x - \frac{7}{2}

Solution steps

Find the line

y = mx + b

parallel to

y = \frac{3}{2} x + 3

that passes through

(1, - 2)

Find the slope of

y = \frac{3}{2} x + 3 : m = \frac{3}{2}

Compute the

y

intercept:

b = - \frac{7}{2}

Construct the line equation

y = mx + b

where

m = \frac{3}{2}

and

b = - \frac{7}{2}

y = \frac{3}{2} x - \frac{7}{2}

f (x) = \frac{x + 16}{x - 12}

3 x^{4} + 8 x^{3}

y = - 3 x^{2} + x + 5

f (x) = 3 x^{3} - 3 x^{2} - 3 x + 7

f (x) = x^{2} - 6 x + 7

What is the parallel y= 3/2 x+3,(1,-2) ?
The parallel y= 3/2 x+3,(1,-2) is y= 3/2 x-7/2