What is the inverse of f(x)=(x+1)/(3-7x) ?

The inverse of f(x)=(x+1)/(3-7x) is -(1-3x)/(1+7x)

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inverse of f(x)=(x+1)/(3-7x)

inverse

f (x) = \frac{x + 1}{3 - 7 x}

- \frac{1 - 3 x}{1 + 7 x}

Solution steps

y = \frac{x + 1}{3 - 7 x}

Replace

x

with

y

x = \frac{y + 1}{3 - 7 y}

Solve for

y, x = \frac{y + 1}{3 - 7 y}

- \frac{1 - 3 x}{1 + 7 x}

f (x) = (x + 2)^{2}

f (x) = 9 x^{7} + 21 x^{6} - 30 x^{5} - 19

- 3 sin (- 2 x + \frac{π}{2})

f (x) = - 3 (x + 1)^{2} + 4

f (x) = 5 x + 4 x - 9

What is the inverse of f(x)=(x+1)/(3-7x) ?
The inverse of f(x)=(x+1)/(3-7x) is -(1-3x)/(1+7x)