What is the domain of f(x)=sqrt((10+x)/(-6+2x)) ?

The domain of f(x)=sqrt((10+x)/(-6+2x)) is x 3

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domain of f(x)=sqrt((10+x)/(-6+2x))

domain

f (x) = \frac{10 + x}{- 6 + 2 x}

x \leq - 10 or x > 3

Interval Notation

(- \infty, - 10] \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 10 or x > 3

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \leq - 10 or x > 3

x^{2} - 2 x - 3

\frac{1}{9} sin (7 x + \frac{π}{2})

\frac{2 x + 3}{5 x + 4}

f (x) = x^{2} - 3 x, g (x) = x - 1, g (x) \circ f (x)

y = x - 4

What is the domain of f(x)=sqrt((10+x)/(-6+2x)) ?
The domain of f(x)=sqrt((10+x)/(-6+2x)) is x<=-10\lor x>3