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Popular >

midpoint (2,-1),(10,7)

Solution

midpoint

(2, - 1), (10, 7)

Solution

(6, 3)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 1), (x_{2}, y_{2}) = (10, 7)

= (\frac{10 + 2}{2}, \frac{7 - 1}{2})

Refine

= (6, 3)

Popular Examples

inflection (e^x)/(1+x)inflection points

\frac{e ^{x}}{1 + x}

asymptotes of f(x)=(x^2+5x-6)/(x+3)asymptotes

f (x) = \frac{x ^{2} + 5 x - 6}{x + 3}

domain of f(x)=2x^2-x-1 domain

f (x) = 2 x^{2} - x - 1

extreme f(x)=x^2e^{-x}extreme points

f (x) = x^{2} e^{- x}

inverse of y=13x+2 inverse

y = 13 x + 2

Frequently Asked Questions (FAQ)

What is the midpoint (2,-1),(10,7) ?
The midpoint (2,-1),(10,7) is (6,3)