What is the domain of f(x)= 1/(x^2+1)-1/(x^2-1) ?

The domain of f(x)= 1/(x^2+1)-1/(x^2-1) is x 1

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domain of f(x)= 1/(x^2+1)-1/(x^2-1)

domain

f (x) = \frac{1}{x ^{2} + 1} - \frac{1}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = x^{\frac{1}{2}} - 7

f (x) = - 4 cos (\frac{2}{5} x) - 2

f (x) = x + 12

3 x^{3} + 2

y = 5 cos (\frac{1}{4} x)

What is the domain of f(x)= 1/(x^2+1)-1/(x^2-1) ?
The domain of f(x)= 1/(x^2+1)-1/(x^2-1) is x<-1\lor-1<x<1\lor x>1