What is the domain of f(x)=((x+1))/(x^2-9) ?

The domain of f(x)=((x+1))/(x^2-9) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((x+1))/(x^2-9)

domain

f (x) = \frac{( x + 1 )}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = 4 + 4 + x

f (x) = - (4 x + 10 y) = - 9

f (x) = \frac{( 3 x - 8 )}{( x ^{2} - 9 x + 20 )}

f (x) = 4 - 5 x^{3}

f (x) = x^{2} + 6 x + 9

What is the domain of f(x)=((x+1))/(x^2-9) ?
The domain of f(x)=((x+1))/(x^2-9) is x<-3\lor-3<x<3\lor x>3