What is the inverse of sqrt(-(x+3)/(16))-7 ?

The inverse of sqrt(-(x+3)/(16))-7 is -16x^2-224x-787

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inverse of sqrt(-(x+3)/(16))-7

inverse

- \frac{x + 3}{16} - 7

- 16 x^{2} - 224 x - 787

Solution steps

y = - \frac{x + 3}{16} - 7

Replace

x

with

y

x = - \frac{y + 3}{16} - 7

Solve for

y, x = - \frac{y + 3}{16} - 7

- 16 x^{2} - 224 x - 787

g (f) = f^{9}

f (x) = 7 - 3 x^{2}

f (x) = - 5

f (x) = \frac{7}{\frac{2}{5} x + \frac{1}{8}}

(- 1.9) (3.3)

What is the inverse of sqrt(-(x+3)/(16))-7 ?
The inverse of sqrt(-(x+3)/(16))-7 is -16x^2-224x-787