What is the domain of f(x)=(x-3)/(\sqrt[3]{x^2-1)} ?

The domain of f(x)=(x-3)/(\sqrt[3]{x^2-1)} is x 1

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domain of f(x)=(x-3)/(\sqrt[3]{x^2-1)}

domain

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

\frac{- 3 x + 9}{x ^{2} + x - 12}

x^{3} - 12 x

f (x) = \frac{x ^{2} - 8 x - 9}{3 x ^{2} + x - 2}

6 x - 4 y = 18

What is the domain of f(x)=(x-3)/(\sqrt[3]{x^2-1)} ?
The domain of f(x)=(x-3)/(\sqrt[3]{x^2-1)} is x<-1\lor-1<x<1\lor x>1