What is the critical (e^x-e^{-x})/9 ?

The critical (e^x-e^{-x})/9 is x=Undefined

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critical (e^x-e^{-x})/9

critical points

\frac{e ^{x} - e ^{- x}}{9}

x = Undefined

Solution steps

\frac{e ^{x} - e ^{- x}}{9}

Find where

f^{'} (x)

is equal to zero or undefined

x = Undefined

Identify critical points not in

f (x)

domain

Domain of

\frac{e ^{x} - e ^{- x}}{9} : - \infty < x < \infty

All critical points are in domain

x = Undefined

f (x) = \frac{1}{x - x ^{2}}

f (x) = (x - 2)^{3}

\frac{x + 9}{x}

\frac{7 x + 2 x}{x}

f (x) = 4 + x + x^{2} - x^{3}

What is the critical (e^x-e^{-x})/9 ?
The critical (e^x-e^{-x})/9 is x=Undefined