What is the inverse of f(x)=(sqrt(2x+3))/5 ?

The inverse of f(x)=(sqrt(2x+3))/5 is (25x^2-3)/2

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inverse of f(x)=(sqrt(2x+3))/5

inverse

f (x) = \frac{2 x + 3}{5}

\frac{25 x ^{2} - 3}{2}

Solution steps

y = \frac{2 x + 3}{5}

Replace

x

with

y

x = \frac{2 y + 3}{5}

Solve for

y, x = \frac{2 y + 3}{5}

\frac{25 x ^{2} - 3}{2}

f (x) = - \frac{1}{5} cos (\frac{1}{5} x)

(0.8) (5.3)

- x^{2} + 2

(6, 1), (1, 3)

f (x) = \frac{7 + x ^{2}}{x + 9}

What is the inverse of f(x)=(sqrt(2x+3))/5 ?
The inverse of f(x)=(sqrt(2x+3))/5 is (25x^2-3)/2