What is the domain of-(13)/((4+t)^2) ?

The domain of-(13)/((4+t)^2) is t -4

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domain of-(13)/((4+t)^2)

domain

- \frac{13}{( 4 + t ) ^{2}}

t < - 4 or t > - 4

Interval Notation

(- \infty, - 4) \cup (- 4, \infty)

Solution steps

Find undefined (singularity) points:

t = - 4

The function domain

t < - 4 or t > - 4

y = \frac{3}{2} x - 3.5

y = - 8 x

f (x) = 2 x + 5 y = - 6

f (x) = \frac{2 x}{x + 3}

f (x) = (x + 1)^{4}

What is the domain of-(13)/((4+t)^2) ?
The domain of-(13)/((4+t)^2) is t<-4\lor t>-4