What is the domain of f(x)=sqrt((x+1)/(x^2-1)) ?

The domain of f(x)=sqrt((x+1)/(x^2-1)) is x>1

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domain of f(x)=sqrt((x+1)/(x^2-1))

domain

f (x) = \frac{x + 1}{x ^{2} - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x > 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x > 1

x^{2} (x - 9)

x - 4 y = 24

f (x) = \frac{3 + x}{1 - x}

f (x) = 3 x^{2} - 2 x - 4

5 x^{2} ln (\frac{x}{2})

What is the domain of f(x)=sqrt((x+1)/(x^2-1)) ?
The domain of f(x)=sqrt((x+1)/(x^2-1)) is x>1