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Popular >

midpoint (-3,-12),(11,-4)

Solution

midpoint

(- 3, - 12), (11, - 4)

Solution

(4, - 8)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 3, - 12), (x_{2}, y_{2}) = (11, - 4)

= (\frac{11 - 3}{2}, \frac{- 4 - 12}{2})

Refine

= (4, - 8)

Popular Examples

inverse of y=sqrt(x-3)inverse

y = x - 3

asymptotes of f(x)=(x^2+3x)/(x^2+5x+6)asymptotes

f (x) = \frac{x ^{2} + 3 x}{x ^{2} + 5 x + 6}

critical f(x)=2sin^2(24x)+3 critical points

f (x) = 2 sin^{2} (24 x) + 3

domain of f(x)=-4 domain

f (x) = - 4

range of (2x^2+8x-24)/(x^2+x-12)range

\frac{2 x ^{2} + 8 x - 24}{x ^{2} + x - 12}

Frequently Asked Questions (FAQ)

What is the midpoint (-3,-12),(11,-4) ?
The midpoint (-3,-12),(11,-4) is (4,-8)