What is the critical ln((2x+3)/(6-x)) ?

The critical ln((2x+3)/(6-x)) is None

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critical ln((2x+3)/(6-x))

critical points

ln (\frac{2 x + 3}{6 - x})

None

Solution steps

ln (\frac{2 x + 3}{6 - x})

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = 6

Identify critical points not in

f (x)

domain

Domain of

ln (\frac{2 x + 3}{6 - x}) : - \frac{3}{2} < x < 6

ln (\frac{2 x + 3}{6 - x})

is not defined at

x = - \frac{3}{2}, x = 6

, therefore:

None

f (x) = - 5 x - 5

f (x) = \frac{6}{x - 9}

y = 2 x^{2} + 5 x - 7

y = - 2 x + 4

f (x) = \frac{3 x}{x - 5}