What is the domain of f(x)=(9x)/(sqrt(-24+3x^3)) ?

The domain of f(x)=(9x)/(sqrt(-24+3x^3)) is x>2

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domain of f(x)=(9x)/(sqrt(-24+3x^3))

domain

f (x) = \frac{9 x}{- 24 + 3 x ^{3}}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

\frac{5 x}{x ^{2} + 1}

3 sin (x + π) - 2

f (x) = x^{\frac{2}{3}} (x - 2)

f (x) = 8 x^{3} - 6

f (x) = \frac{x}{3}

What is the domain of f(x)=(9x)/(sqrt(-24+3x^3)) ?
The domain of f(x)=(9x)/(sqrt(-24+3x^3)) is x>2