What is the domain of f(x)=(sqrt(2+x))/(3-x) ?

The domain of f(x)=(sqrt(2+x))/(3-x) is -2 3

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domain of f(x)=(sqrt(2+x))/(3-x)

domain

f (x) = \frac{2 + x}{3 - x}

- 2 \leq x < 3 or x > 3

Interval Notation

[- 2, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 2 \leq x < 3 or x > 3

f (x) = 8 x - 10

f (x) = \frac{x ^{2} - 144}{x + 12}

y = - \frac{x}{6} - 2, (9, - 2)

f (x) = - 2 - sin (2 x)

f (x) = x^{3} + 3 x + 1

What is the domain of f(x)=(sqrt(2+x))/(3-x) ?
The domain of f(x)=(sqrt(2+x))/(3-x) is -2<= x<3\lor x>3