What is the inverse of g(x)=3log_{5}(x+1)-2 ?

The inverse of g(x)=3log_{5}(x+1)-2 is 5^{(x+2)/3}-1

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inverse of g(x)=3log_{5}(x+1)-2

inverse

g (x) = 3 lo g_{5} (x + 1) - 2

5^{\frac{x + 2}{3}} - 1

Solution steps

y = 3 lo g_{5} (x + 1) - 2

Replace

x

with

y

x = 3 lo g_{5} (y + 1) - 2

Solve for

y, x = 3 lo g_{5} (y + 1) - 2

5^{\frac{x + 2}{3}} - 1

(6, - 8), (- 4, - 2)

f (x) = \frac{x ^{2}}{x - 1}

\frac{1}{x ^{3}}

(4, 2), (- 3, 2)

\frac{x - 1}{x ^{2}}

What is the inverse of g(x)=3log_{5}(x+1)-2 ?
The inverse of g(x)=3log_{5}(x+1)-2 is 5^{(x+2)/3}-1