What is the domain of f(x)=sqrt((4-3n)) ?

The domain of f(x)=sqrt((4-3n)) is n<= 4/3

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domain of f(x)=sqrt((4-3n))

domain

f (x) = (4 - 3 n)

n \leq \frac{4}{3}

Interval Notation

(- \infty, \frac{4}{3}]

Solution steps

Find non-negative values for radicals:

n \leq \frac{4}{3}

The function domain

n \leq \frac{4}{3}

f (x) = \frac{x ^{2} - x}{x - 2}

f (x) = - 27 x^{3} + 9 x + 6

\frac{x - 4}{x ^{3} - 5 x ^{2} + 12 x - 33}

f (x) = lo g_{2} (- x - 1) + 3

What is the domain of f(x)=sqrt((4-3n)) ?
The domain of f(x)=sqrt((4-3n)) is n<= 4/3