What is the critical f(x)=5x^4+8x^3+2x^2 ?

The critical f(x)=5x^4+8x^3+2x^2 is x=-1,x=-1/5 ,x=0

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critical f(x)=5x^4+8x^3+2x^2

critical points

f (x) = 5 x^{4} + 8 x^{3} + 2 x^{2}

x = - 1, x = - \frac{1}{5}, x = 0

Solution steps

5 x^{4} + 8 x^{3} + 2 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = - \frac{1}{5}, x = 0

Identify critical points not in

f (x)

domain

Domain of

5 x^{4} + 8 x^{3} + 2 x^{2} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = - \frac{1}{5}, x = 0

f (x) = 10

(13, 0), (15, 1)

9 t - 2 t^{2}

y (X) = - X^{2}

\frac{- 3 x + 10}{2 x}

What is the critical f(x)=5x^4+8x^3+2x^2 ?
The critical f(x)=5x^4+8x^3+2x^2 is x=-1,x=-1/5 ,x=0