What is the inflection f(x)=x^3-2x^2-4x+3 ?

The inflection f(x)=x^3-2x^2-4x+3 is (2/3 ,-7/27)

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inflection f(x)=x^3-2x^2-4x+3

inflection points

f (x) = x^{3} - 2 x^{2} - 4 x + 3

(\frac{2}{3}, - \frac{7}{27})

Solution steps

f^{''} (x) = 6 x - 4

Find intervals:

Concave Downward

: - \infty < x < \frac{2}{3},

Concave Upward

: \frac{2}{3} < x < \infty

Plug

x = \frac{2}{3}

into

x^{3} - 2 x^{2} - 4 x + 3 : - \frac{7}{27}

(\frac{2}{3}, - \frac{7}{27})

f (x) = \frac{3}{x - 7}

p = 15 n + 300

x - 1 + 3

2 x - 3

f (x) = \frac{4 x - 36 x}{3 x - 27}

What is the inflection f(x)=x^3-2x^2-4x+3 ?
The inflection f(x)=x^3-2x^2-4x+3 is (2/3 ,-7/27)