What is the perpendicular y=-1/6 x+3,(1,10) ?

The perpendicular y=-1/6 x+3,(1,10) is y=6x+4

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perpendicular y=-1/6 x+3,(1,10)

perpendicular

y = - \frac{1}{6} x + 3, (1, 10)

y = 6 x + 4

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{1}{6} x + 3

that passes through

(1, 10)

Find the slope of

y = - \frac{1}{6} x + 3 : m = - \frac{1}{6}

Compute the slope of the perpendicular line:

m_{p} = 6

Find the line with slope m=

6

and passing through

(1, 10) : y = 6 x + 4

y = 6 x + 4

f (x) = - x - 5

- x^{2} + 4 x - 3

f (x) = x^{3} - x

100

(- 1, 5), (2, - 3)

What is the perpendicular y=-1/6 x+3,(1,10) ?
The perpendicular y=-1/6 x+3,(1,10) is y=6x+4