What is the domain of f(x)=(4(x+1)(x-2))/(x(x-3)) ?

The domain of f(x)=(4(x+1)(x-2))/(x(x-3)) is x 3

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domain of f(x)=(4(x+1)(x-2))/(x(x-3))

domain

f (x) = \frac{4 ( x + 1 ) ( x - 2 )}{x ( x - 3 )}

x < 0 or 0 < x < 3 or x > 3

Interval Notation

(- \infty, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 3

The function domain

x < 0 or 0 < x < 3 or x > 3

\frac{x ^{2} - 1}{x ^{2} - 4}

y = \frac{5 x + 1}{2 x - 5}

3 x^{4} - 18 x^{2}

y = 2 x - 1

f (x) = \frac{x ^{2} + 2 x}{2 x ^{2} - 7 x}

What is the domain of f(x)=(4(x+1)(x-2))/(x(x-3)) ?
The domain of f(x)=(4(x+1)(x-2))/(x(x-3)) is x<0\lor 0<x<3\lor x>3