What is the inverse of f(x)=x^2-11,x>= 0 ?

The inverse of f(x)=x^2-11,x>= 0 is sqrt(x+11),-sqrt(x+11)

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inverse of f(x)=x^2-11,x>= 0

inverse

f (x) = x^{2} - 11, x \geq 0

x + 11, - x + 11

Solution steps

y = x^{2} - 11

Replace

x

with

y

x = y^{2} - 11

Solve for

y, x = y^{2} - 11

x + 11, - x + 11

f (x) = \frac{5 x}{x - 4}

f (x) = x + \frac{17}{x}

f (x) = \frac{x - 3}{5} + 2

f (x) = 3 (x + 1)^{3}

y = ln (x)

What is the inverse of f(x)=x^2-11,x>= 0 ?
The inverse of f(x)=x^2-11,x>= 0 is sqrt(x+11),-sqrt(x+11)