What is the range of f(x)=(1/2)^x ?

The range of f(x)=(1/2)^x is f(x)>0

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range of f(x)=(1/2)^x

range

f (x) = (\frac{1}{2})^{x}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = 0

f (x) > 0

f (x) = \frac{x - 1}{x + 2}

f (x) = \frac{3}{- x + 3} - 1

f (x) = \frac{x}{x ^{2} - 1}

\frac{4 x ^{2} - 5}{2 x ^{2} + 8}

f (x) = \frac{x + 6}{x ^{2} + 6 x + 5}