What is the range of y=\sqrt[3]{x-1} ?

The range of y=\sqrt[3]{x-1} is -infinity <f(x)<infinity

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range of y=\sqrt[3]{x-1}

range

y = 3 x - 1

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

3 x - 1

Inverse of

3 x - 1 : x^{3} + 1

x^{3} + 1

Find the domain of each inverse function

Domain of

x^{3} + 1 : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

f (x) = 3^{x - 2} - 4

\frac{x + y}{- 5} + 10 = - 23

f (x) = - 4 cot (3 x)

y = - 4 x + 1, (2, 8)

f (x) = 4 y - 3

What is the range of y=\sqrt[3]{x-1} ?
The range of y=\sqrt[3]{x-1} is -infinity <f(x)<infinity