What is the asymptotes of y=-2(1/2)^x ?

The asymptotes of y=-2(1/2)^x is Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of y=-2(1/2)^x

asymptotes

y = - 2 (\frac{1}{2})^{x}

Horizontal : y = 0

Solution steps

Vertical asymptotes of

- 2 (\frac{1}{2})^{x} :

None

Horizontal Asymptotes of

- 2 (\frac{1}{2})^{x} : y = 0

Slant Asymptotes of

- 2 (\frac{1}{2})^{x} :

None

Horizontal : y = 0

(8, 4), (1, - 3)

y = \frac{x ^{2} - 5}{x ^{4} + 16}

f (x) = x^{2} + 6 x + 9

f (x) = x^{2} + 4 x + 5

f (x) = 6 - 5 x

What is the asymptotes of y=-2(1/2)^x ?
The asymptotes of y=-2(1/2)^x is Horizontal: y=0