What is the domain of f(x)=ln(x^4-1) ?

The domain of f(x)=ln(x^4-1) is x 1

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domain of f(x)=ln(x^4-1)

domain

f (x) = ln (x^{4} - 1)

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

f (x) = - x^{2} + 3 x + 7

y = x^{2} - 3

\frac{x + 21}{x - 7}

f (x) = \frac{2 x}{x + 1}

f (x) = 1 + \frac{1}{x}

What is the domain of f(x)=ln(x^4-1) ?
The domain of f(x)=ln(x^4-1) is x<-1\lor x>1