What is the extreme f(x)=4x^3-48x ?

The extreme f(x)=4x^3-48x is Maximum(-2,64),Minimum(2,-64)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=4x^3-48x

extreme points

f (x) = 4 x^{3} - 48 x

Maximum (- 2, 64), Minimum (2, - 64)

Solution steps

f^{'} (x) = 12 x^{2} - 48

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

4 x^{3} - 48 x : 64

Maximum (- 2, 64)

Plug

x = 2

into

4 x^{3} - 48 x : - 64

Minimum (2, - 64)

Maximum (- 2, 64), Minimum (2, - 64)

6 (x - 8)^{2} + 7

\frac{x ^{\frac{2}{3}}}{1 + x + x ^{4}}

f (x) = \frac{x + 3}{( x + 8 ) ( x - 2 )}

\frac{3 x}{x ^{2} + 3}

f (x) = \frac{x + 1}{x - 3}

What is the extreme f(x)=4x^3-48x ?
The extreme f(x)=4x^3-48x is Maximum(-2,64),Minimum(2,-64)