What is the perpendicular y= 3/4 x,(20,15) ?

The perpendicular y= 3/4 x,(20,15) is y=-4/3 x+125/3

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perpendicular y= 3/4 x,(20,15)

perpendicular

y = \frac{3}{4} x, (20, 15)

y = - \frac{4}{3} x + \frac{125}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{4} x

that passes through

(20, 15)

Find the slope of

y = \frac{3}{4} x : m = \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = - \frac{4}{3}

Find the line with slope m=

- \frac{4}{3}

and passing through

(20, 15) : y = - \frac{4}{3} x + \frac{125}{3}

y = - \frac{4}{3} x + \frac{125}{3}

y = 4 - \frac{1}{2 x + 1}

f (x) = \frac{2 x}{( x - 3 ) ^{2}}

\frac{x ^{3} - x}{x ^{2} - 6 x + 5}

x - 3 = 0

What is the perpendicular y= 3/4 x,(20,15) ?
The perpendicular y= 3/4 x,(20,15) is y=-4/3 x+125/3