What is the domain of f(x)= 1/(x^2+3x-54) ?

The domain of f(x)= 1/(x^2+3x-54) is x 6

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domain of f(x)= 1/(x^2+3x-54)

domain

f (x) = \frac{1}{x ^{2} + 3 x - 54}

x < - 9 or - 9 < x < 6 or x > 6

Interval Notation

(- \infty, - 9) \cup (- 9, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 9

The function domain

x < - 9 or - 9 < x < 6 or x > 6

1 - tan (π - x)

f (x) = ln (- x)

x^{4} - 16 x^{2}

y = \frac{x ^{2} - x}{x ^{2} - 9 x + 8}

f (x) = (x - 1)^{2}, x \geq 1

What is the domain of f(x)= 1/(x^2+3x-54) ?
The domain of f(x)= 1/(x^2+3x-54) is x<-9\lor-9<x<6\lor x>6