What is the monotone (8x)/(x^2+1) ?

The monotone (8x)/(x^2+1) is Decreasing:-infinity <x<-1,Increasing:-1<x<1,Decreasing:1<x<infinity

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monotone (8x)/(x^2+1)

monotone intervals

\frac{8 x}{x ^{2} + 1}

Decreasing : - \infty < x < - 1, Increasing : - 1 < x < 1, Decreasing : 1 < x < \infty

Solution steps

f^{'} (x) = \frac{8 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Decreasing : - \infty < x < - 1, Increasing : - 1 < x < 1, Decreasing : 1 < x < \infty

f (x) = \frac{2 x + 1}{x ^{2} + 2 x - 3}

\frac{x ^{3} + x ^{2}}{x ^{2} - 4}

tan^{\frac{1}{2}} (x) d x

f (x) = x^{3} - 8

f (x) = x e^{\frac{1}{x ^{2}}}

What is the monotone (8x)/(x^2+1) ?
The monotone (8x)/(x^2+1) is Decreasing:-infinity <x<-1,Increasing:-1<x<1,Decreasing:1<x<infinity