What is the asymptotes of f(x)=(sqrt(4x^2+2))/(2x-1) ?

The asymptotes of f(x)=(sqrt(4x^2+2))/(2x-1) is Vertical: x= 1/2 ,Horizontal: y=1,y=-1

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asymptotes of f(x)=(sqrt(4x^2+2))/(2x-1)

asymptotes

f (x) = \frac{4 x ^{2} + 2}{2 x - 1}

Vertical : x = \frac{1}{2}, Horizontal : y = 1, y = - 1

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 2}{2 x - 1} : x = \frac{1}{2}

Horizontal Asymptotes of

\frac{4 x ^{2} + 2}{2 x - 1} : y = 1, y = - 1

Slant Asymptotes of

\frac{4 x ^{2} + 2}{2 x - 1} :

None

Vertical : x = \frac{1}{2}, Horizontal : y = 1, y = - 1

- 4 x^{4} + 3 x^{3} + 3 x^{2}

f (x) = \frac{3 x - 1}{( 2 x + 3 ) ( 2 x - 3 )}

(- 4, 2), (2, 4)

f (x) = \frac{x ^{2} + 1 + 8 x}{x ^{2} + 1 + 2 x}

f (x) = x^{2} - 2 x + 3

What is the asymptotes of f(x)=(sqrt(4x^2+2))/(2x-1) ?
The asymptotes of f(x)=(sqrt(4x^2+2))/(2x-1) is Vertical: x= 1/2 ,Horizontal: y=1,y=-1