What is the inverse of f(x)=3x^2-5 ?

The inverse of f(x)=3x^2-5 is sqrt((x+5)/3),-sqrt((x+5)/3)

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inverse of f(x)=3x^2-5

inverse

f (x) = 3 x^{2} - 5

\frac{x + 5}{3}, - \frac{x + 5}{3}

Solution steps

y = 3 x^{2} - 5

Replace

x

with

y

x = 3 y^{2} - 5

Solve for

y, x = 3 y^{2} - 5

\frac{x + 5}{3}, - \frac{x + 5}{3}

ln (x - 1)

f (x) = 2 sin (\frac{1}{3} x - π) - 4

f (x) = \frac{1}{4} x + 2

- 3

f (x) = (x - 3)^{\frac{1}{2}}

What is the inverse of f(x)=3x^2-5 ?
The inverse of f(x)=3x^2-5 is sqrt((x+5)/3),-sqrt((x+5)/3)