What is the inverse of f(x)=((2x+1))/(x-3) ?

The inverse of f(x)=((2x+1))/(x-3) is (1+3x)/(x-2)

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inverse of f(x)=((2x+1))/(x-3)

inverse

f (x) = \frac{( 2 x + 1 )}{x - 3}

\frac{1 + 3 x}{x - 2}

Solution steps

y = \frac{2 x + 1}{x - 3}

Replace

x

with

y

x = \frac{2 y + 1}{y - 3}

Solve for

y, x = \frac{2 y + 1}{y - 3}

\frac{1 + 3 x}{x - 2}

f (x) = \frac{5 x}{3 x ( x + 12 )}

f (x) = e^{6 x - 5}

f (x) = \frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9}

f (x) = 5 x + (5 x - 6)

f (x) = x^{2} + 5 x + 6

What is the inverse of f(x)=((2x+1))/(x-3) ?
The inverse of f(x)=((2x+1))/(x-3) is (1+3x)/(x-2)