What is the inverse of g(x)=(3x-8)/(8x+1) ?

The inverse of g(x)=(3x-8)/(8x+1) is (-8-x)/(8x-3)

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inverse of g(x)=(3x-8)/(8x+1)

inverse

g (x) = \frac{3 x - 8}{8 x + 1}

\frac{- 8 - x}{8 x - 3}

Solution steps

y = \frac{3 x - 8}{8 x + 1}

Replace

x

with

y

x = \frac{3 y - 8}{8 y + 1}

Solve for

y, x = \frac{3 y - 8}{8 y + 1}

\frac{- 8 - x}{8 x - 3}

y = 6 x

y = 1

x + 7

y = e^{2 x - 3}

2 x - 5 y = 0

What is the inverse of g(x)=(3x-8)/(8x+1) ?
The inverse of g(x)=(3x-8)/(8x+1) is (-8-x)/(8x-3)