What is the range of f(x)=sqrt(x/4) ?

The range of f(x)=sqrt(x/4) is f(x)>= 0

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range of f(x)=sqrt(x/4)

range

f (x) = \frac{x}{4}

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x}{4} : x \geq 0

Extreme Points of

\frac{x}{4} :

Minimum

(0, 0)

Find the range for the interval

0 \leq x < \infty : 0 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 0

y - 5 x = 5

f (x) = x - 8

\frac{4 x ^{2} + 1}{x ^{2} + x + 16}

f (x) = ln (x) + ln (3 - x)

f (x) = x^{3} - \frac{1}{x}